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		<title><![CDATA[Gentoo中文社区 / C 练习实例1]]></title>
		<link>https://www.gentoo-zh.org/viewtopic.php?id=310</link>
		<description><![CDATA[C 练习实例1 最近发表的帖子。]]></description>
		<lastBuildDate>Mon, 29 Aug 2022 06:55:09 +0000</lastBuildDate>
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			<title><![CDATA[C 练习实例1]]></title>
			<link>https://www.gentoo-zh.org/viewtopic.php?pid=316#p316</link>
			<description><![CDATA[<p>题目：有 1、2、3、4 四个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？</p><p>程序分析：可填在百位、十位、个位的数字都是 1、2、3、4，组成所有的排列后再去掉不满足条件的排列。</p><br /><br /><br /><p>#include&lt;stdio.h&gt;</p><p>int main()<br />{<br />&#160; &#160; int i,j,k;<br />&#160; &#160; printf(&quot;\n&quot;);<br />&#160; &#160; for(i=1;i&lt;5;i++) { // 以下为三重循环<br />&#160; &#160; &#160; &#160; for(j=1;j&lt;5;j++) {<br />&#160; &#160; &#160; &#160; &#160; &#160; for (k=1;k&lt;5;k++) { // 确保i、j、k三位互不相同<br />&#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; if (i!=k&amp;&amp;i!=j&amp;&amp;j!=k) { <br />&#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; printf(&quot;%d,%d,%d\n&quot;,i,j,k);<br />&#160; &#160; &#160; &#160; &#160; &#160; &#160; &#160; }<br />&#160; &#160; &#160; &#160; &#160; &#160; }<br />&#160; &#160; &#160; &#160; }<br />&#160; &#160; }<br />}</p>]]></description>
			<author><![CDATA[dummy@example.com (batsom)]]></author>
			<pubDate>Mon, 29 Aug 2022 06:55:09 +0000</pubDate>
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