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		<title><![CDATA[Gentoo中文社区 / C 练习实例8]]></title>
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		<description><![CDATA[C 练习实例8 最近发表的帖子。]]></description>
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			<title><![CDATA[C 练习实例8]]></title>
			<link>https://www.gentoo-zh.org/viewtopic.php?pid=323#p323</link>
			<description><![CDATA[<p>题目：输出9*9口诀。</p><p>程序分析：分行与列考虑，共 9 行 9 列，i 控制行，j 控制列。</p><p>程序源代码：</p><p>#include&lt;stdio.h&gt;<br />int main()<br />{<br />&#160; &#160; int i,j,result;<br />&#160; &#160; printf(&quot;\n&quot;);<br />&#160; &#160; for (i=1;i&lt;10;i++)<br />&#160; &#160; {<br />&#160; &#160; &#160; &#160; for(j=1;j&lt;=i;j++)<br />&#160; &#160; &#160; &#160; {<br />&#160; &#160; &#160; &#160; &#160; &#160; result=i*j;<br />&#160; &#160; &#160; &#160; &#160; &#160; printf(&quot;%d*%d=%-3d&quot;,i,j,result); /*-3d表示左对齐，占3位*/<br />&#160; &#160; &#160; &#160; }<br />&#160; &#160; printf(&quot;\n&quot;); /*每一行后换行*/<br />&#160; &#160; }<br />}</p>]]></description>
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			<pubDate>Mon, 29 Aug 2022 06:59:34 +0000</pubDate>
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